How to make a statement true for column 5-6?
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I have a matrix
M= [1 50 60 70 50 40
2 NaN 10 20 10 10
3 NaN 20 NaN NaN NaN
1 NaN 60 30 40 50
2 10 20 10 20 NaN
1 30 20 40 NaN 50
2 NaN 50 50 1 NaN];
I want to check that, for each row, whether it is ture that the element in column 2 is NaN and the elements in column 5-6 are both non-NaN. I tried to code like this:
P=isnan(M(:,2))&isfinite(M(:,5:6))
However, the result is in 2 columns, column "NaN in column 2 and non-NaN in column 5" and column "NaN in column 2 and non-NaN in column 6".
Could anyone please tell me how to have the answer in 1 column?
I think this code works,
P=isnan(M(:,2))&isfinite(M(:,5))&isfinite(M(:,6))
but is there a better way to express "column 5-6" instead of making a isfinite statement for each column seperately?
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