Maxtrix copy and manipulation

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Fischer Zheng
Fischer Zheng on 17 Sep 2015
Edited: Matt J on 18 Sep 2015
I have one matrix and one vector. I would like to shift the elements of row forward depending on the vector index.
M = [0 2 4 5;
0 4 7 9;
0 0 0 34];
v = [4 3 2];
Shift the elements of M forward, v(1) = 4 indicate start result with the 4th element of the row. Pad the end of row with zeros.
Result = [5 0 0 0;
7 9 0 0;
0 0 34 0]
How do I do this in the vectorized way?
Thanks, Fischer

Accepted Answer

Star Strider
Star Strider on 17 Sep 2015
This uses a loop, but I can’t see how to do this without one:
M = [0 2 4 5; 0 4 7 9; 0 0 0 34];
v = [4 3 2];
c = size(M,2);
Result = zeros(size(M));
for k1 = 1:size(M,1)
Result(k1,1:c-v(k1)+1) = M(k1,v(k1):c);
end
  5 Comments
Star Strider
Star Strider on 17 Sep 2015
Thank you.
If you’re doing this once for each large matrix, save the shifted matrix to a .mat file. Then you can simply load the shifted matrix when you need it, rather than recalculating it each time.

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More Answers (1)

Matt J
Matt J on 17 Sep 2015
Edited: Matt J on 18 Sep 2015
v=v(:);
[m,n]=size(M);
[I,J,S]=find(M);
J=J-v(I)+1;
idx=J>0;
Result=sparse(I(idx),J(idx),S(idx),m,n);
Result=full(Result); %optional
  1 Comment
Fischer Zheng
Fischer Zheng on 17 Sep 2015
Edited: Fischer Zheng on 17 Sep 2015
Thanks for the update. Let me take a look again.
Thanks,

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