how to minimize a parameter
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Hi, mi programm is this one
function theoretical1
clc;
clear all;
close all;
tau1=147;
k0=[150000 1.5 1.5 1.5];
nu=[-1; -5 ;-6]; % stoichiometrical matrix of coefficients
C01 = [0.00005 0.001 0.05]; % initial concentratio of measure j
[time1,C1]= ode45(@myode1,[0 tau1],C01);
function dC1dt=myode1(t,C)
R1=k0(1)*C(1)^k0(2)*C(2)^k0(3)*C(3)^k0(4);
r1=nu*R1;
dC1dt=r1;
end
%Volume
V=0.5;
%species A B and C refer to KIO3 KI and H
%Test one
load ('prova1.mat','seconds','absorbance')
csi1_1=0.2276*absorbance/1000; %in mol/L (M)
sec_1=seconds;
%Initial Concentrations
C0_1=[0.00005 0.001 0.05]; %species A,B and C
C0_A_1=C0_1(1); %conc OF IO3- in mol/L
C0_B_1=C0_1(2); %conc OF I- in mol/L
C0_C_1=C0_1(3); %conc OF H+ in mol/L
%Concentration in time
%from excel plot we know that there is a correlation between absorbance and
%the concentration of I2 that follows a linear rule as follows: C=0.081*A
C_A_1=C0_A_1-csi1_1;
CI2_1=absorbance*0.081/1000;
csi2_1=3*csi1_1-CI2_1; %mol/L
C_B_1=C0_B_1-5*csi1_1-csi2_1;
C_C_1=C0_C_1-6*csi1_1;
C_exp_1=[C_A_1 C_B_1 C_C_1];
err1=[C1(2)-C_A_1 C1(3)-C_B_1 C1(4)-C_C_1];
N1=norm(err1);
end
I have some experimental values of concentration C given and I have to hypothize the values of of the vector k0 in order to calculate a theoretical concentration. What I would like to do now is to minimize the norm N1 by optimizing the values of k0. I know that there are some functions as fminsearch but I really don't know how to use them. Can someone help me with this? Thank you
Answers (2)
Alan Weiss
on 24 Feb 2016
0 votes
2 Comments
Gisela
on 24 Feb 2016
Alan Weiss
on 24 Feb 2016
Perhaps this example will help. It uses patternsearch instead of fmincon, but fmincon works, too, especially if you set larger-than-default finite differences.
Good luck,
Alan Weiss
MATLAB mathematical toolbox documentation
Star Strider
on 24 Feb 2016
0 votes
I cannot follow your code, but if you want to fit data using an ODE in your objective function, see: Monod kinetics and curve fitting.
4 Comments
Gisela
on 25 Feb 2016
Set
B0 = [k1 a b c]
Time = Vector of the times when the measurements were performed
(threefold repeated) [0 0 0 t1 t1 t1 t2 t2 t2 ... tn tn tn]
Sdata = Vector of concentrations at the time instants for the three components
[C01 C02 C03 C11 C12 C13 C21 C22 C23 ... Cn1 Cn2 Cn3]
x0 = Vector of initial concentrations [C01 C02 C03]
t in the call to ODE45 = [0 t1 t2 ... tn]
S = [Sv(1,1) Sv(1,2) Sv(1,3) Sv(2,1) Sv(2,2) Sv(2,3) ... Sv(n+1,1) Sv(n+1,2) Sv(n+1,3)]
Best wishes
Torsten.
Gisela
on 25 Feb 2016
Torsten
on 25 Feb 2016
Yes, lsqcurvefit automatically forms the sum of squared differences between S and Sdata.
Best wishes
Torsten.
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