Can anyone help me with fourier series of a signal?

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I got a signal as attached. My doubt is can I break the signal in a triangle and a straight line, then calculating fourier series for each. Will this break may affect my answer (magnitude * frequency)
  3 Comments
Ajay Goyal
Ajay Goyal on 11 Aug 2016
https://i.snag.gy/EYDexk.jpg Sir, please check the attached image
Image Analyst
Image Analyst on 12 Aug 2016
I meant post it here with the green and brown frame icon. Here, I will do it for you:

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Accepted Answer

Star Strider
Star Strider on 11 Aug 2016
If you’re doing a numeric fft, do the Fourier Transform of the entire signal.
To do it symbolically, separate it into two segments for each part of the triangle, and add:
syms w t f1(t) f2(t)
f1(t) = 40*t;
f2(t) = 40-40*t;
F(w) = int(f1(t)*exp(1i*w*t), t, 0, 0.5) + int(f2(t)*exp(1i*w*t), t, 0.5, 1);
F(w) = simplify(F(w), 'steps',20)
F(w) =
-(40*(exp((w*1i)/2) - 1)^2)/w^2
It is zero elsewhere, so you can ignore that section.
  2 Comments
Ajay Goyal
Ajay Goyal on 11 Aug 2016
Edited: Ajay Goyal on 11 Aug 2016
Thank you very much Sir. My use of FS is restricted to collection of all peak magnitudes and respective frequencies of each sine and cosine wave generated from FS for the given signal. As I have understood from your last statement that I can ignore the straight line of zero magniture. Can I continue my research work by calculating FS of triangle waveform (as I am not using FFT)? I have prepared attached code.
Star Strider
Star Strider on 12 Aug 2016
My pleasure.
Your code is very difficult to follow. Instead of using separate sine and cosine terms, I would use the complex exponential to calculate the Fourier transform.
For a single pulse, you can ignore the zero segment. If your pulse repeats at regular intervals, you must include at least two pulses, with the pulses defined just as the first one was, as segments of straight lines (in this example), each with appropriate slopes and intercepts and integrated over the appropriate time intervals. The zero-value interval is implicit in those integrations, but does not have to be specifically included.

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