what can I do?

if I have a list of numbers and I want to know where a number lies between two numbers in that list.

[Roger Stafford]

Please give more details in your question! Better still, give a concrete example of the "list" and precisely what results you wish to obtain from it.

[khamiis E]

Answer 1

[Guillaume]

A = [10 25
    30 45
    50 150
    300 450
    500 501
    502 600
    630 700
    720 800
    801 815
    820 1000];
B = 33;

find(B >= A(:, 1) & B <= A(:, 2))

[khamiis E]

thanks for your answer

Answer 2

[Walter Roberson]

Suppose you have a vector of values in sorted order, and have some other values, and you want to know where in the vector the other values would sit. Then:

[~, ~, binnumber] = histcounts(TheOtherValues, TheVectorOfFixedValues);

Then, TheOtherValues(K) is between TheVectorOfFixedValues(binnumber(K)) and the next value.

[khamiis E]

Thanks alot for your answer. I can't find the histcounts() function. Is there alternative function?

[Star Strider]

The previous histcounts function was called histc with a slightly different calling and output syntax.

[Walter Roberson]

[~, binnumber] = histc(TheOtherValues, TheVectorOfFixedValues);

[Walter Roberson]

Note: this code was written assuming that your ranges had no gaps, but it appears from your diagram that it does not apply.

[khamiis E]

I really appreciate your effort . thanks for your time and your answer

Answer 3

[Andrei Bobrov]

A = [10 25
    30 45
    50 150
    300 450
    500 501
    502 600
    630 700
    720 800
    801 815
    820 1000]; % your "start-end"

B = [33 300 501 75 754 809 1000 47]'; % Let B - your numbers

b = prod(A - reshape(B,1,1,[]),2);
out = sum(bsxfun(@times,squeeze(b < 0 | b == 0),(1:size(A,1))'))

[khamiis E]

I really appreciate your effort . Thanks for your answer.