slope at defined co-ordinates

Hello I have defined my distance function as

 d = (5757*x^3)/100000 - (2227*x^2)/10000 + (1303*x)/2500 + 25/2

I then differentiate this to get diff

 (5757*x^3)/100000 - (2227*x^2)/10000 + (1303*x)/2500 + 25/2

 ans =
 (1303*x)/2500 - (4999*x^2)/100000 + 25/2

how would I calculate the gradient at varying X values?

Thanks. Gav.

Answer 1

[Star Strider]

The gradient is simply the derivative, since yours is a univariate function. I would create a vectorized anonymous function from it, and use it as I would any other function:

dd_dx = @(x) (1303*x)/2500 - (4999*x.^2)/100000 + 25/2;

then call it as:

x = linspace(0, 10);

figure(1)
plot(x, dd_dx(x))
grid