what is mean by this
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S(i).xd=rand(1,1)*xm;
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Answers (4)
ES
on 3 Aug 2017
S is an array of structures.
xd is one of the members of the structure (type unknown).
In the given line, member xd of the i'th structure is updated with a random number (generated using rand function) multiplied by xm.
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Star Strider
on 3 Aug 2017
It sets the ‘xd’ field of the i-th element of structure ‘S’ to rand times a variable called ‘xm’. The ‘(1,1)’ argument to rand is redundant, since a single call to rand returns a single random scalar value.
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Star Strider
on 3 Aug 2017
Please see the documentation on structures that I linked to in my Answer.
It explains their use and addressing much better than I can.
Jan
on 3 Aug 2017
@Junaid Qadar: The forum is not the best location to clarify the basics of Matlab. Please read the documentation of the concerned command and the Getting Started chapters for this. See also https://matlabacademy.mathworks.com/ -> Onramp
ES
on 4 Aug 2017
Edited: ES
on 4 Aug 2017
There are a number of nodes in your problem - denoted by "NumberOfNodes".
xd, yd, E, R are properties of each of these nodes. The properties of the nodes are stored in a array of structures in this case. where S(1) denotes the properties of Node 1 and so on.
The piece of code you have put, sets the properties for all the nodes iteratively.
xd is set to random number * width;
yd is set to random number * depth;
E is set to E0
R is set to R0
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Abilasha
on 25 Jul 2023
kindly explain this code, its in leach protocol matlab code
figure(1);
for i=1:1:n
S(i).xd=rand(1,1)*xm;
S(i).yd=rand(1,1)*ym;
S(i).G=0;
S(i).type='N';
temp_rnd0=i;
1 Comment
Walter Roberson
on 25 Jul 2023
xd is set to a random number times xm. In other words the x coordinate is set to a random position in the range 0 to xm (maximum x). Likewise the y coordinate is set to a random location in the range 0 to ym.
(Note: the results can never be exactly 0 or exactly xm or ym because of the details of rand().)
You are generating a random position inside a rectangle.
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