identifying the elements of a cell

I have a 700x8 cell, with each cell having a matrix 6x2 in size. I want to get the first row of each cell. How do I perform this?

Answer 1

[Mandeep Singh]

From my understanding of the question, you can achieve the required task by following snippet of code:

cnt = 1;
for i = 1:700
  for j = 1:8
    a(cnt) = C{i,j}(1,:);  % stores the first row of each cell in a;
    cnt = cnt + 1;
  end
end

[Sammit Jain]

I think using a for loop will be slightly computationally expensive in this case.

Answer 2

[Sammit Jain]

Hi, This seems to be a simple case of cell indexing.

Let's call your original cell array (of cells) 'mainCellArray'

Now, let's have allRowsArray = [mainCellArray{:}] Then, firstRowArray = [allRowsArray{1,:}]

Essentially, we're first re-arranging the contents of the main cell array, stacking them one next to the other, then we just index the first row.

Here's what the code should look like:

allRowsArray = [mainCellArray{:}];
firstRowArray = [allRowsArray{1,:}]

Hope this helps. If in case you want to pick a different combination of rows/columns, then just try to transpose these concatenations and see if you get what you want.

Cheers.