Convert cross sectional data into surface
    3 views (last 30 days)
  
       Show older comments
    
    Hassan Qandil
 on 19 Aug 2018
  
    
    
    
    
    Commented: Star Strider
      
      
 on 8 Oct 2020
            Hi, I have a set of cross sectional data distribution on a certain surface:
[5.8645 11.4836 12.6726 11.587 11.3566 10.2168 9.8317 10.0888 10.6236 10.8221 10.8221 10.6236 10.0888 9.8317 10.2168 11.3566 11.587 12.6726 11.4836 5.8645]
It's symmetrical around the center, how can I create a surface from this data?
3 Comments
Accepted Answer
  Star Strider
      
      
 on 26 Aug 2018
        Here is one possible approach.
The Code —
V = [5.8645 11.4836 12.6726 11.587 11.3566 10.2168 9.8317 10.0888 10.6236 10.8221 10.8221 10.6236 10.0888 9.8317 10.2168 11.3566 11.587 12.6726 11.4836 5.8645];
Av = linspace(-1, 1, numel(V))*(10*pi/numel(V));
Rv = linspace(-1, 1, numel(V));
[R,A] = meshgrid(Rv,Av);
Z = ones(numel(Av),1)*V;
[X,Y,Z] = pol2cart(A, R, Z);
figure
surf(X, Y, Z)
grid on
shading(gca,'interp')
view(-30, 50)
The Plot —

You will have to experiment to get the result you want, including labeling the axis ticks as you want them.
This will get you started.
4 Comments
  Taiwo Ajayi
 on 8 Oct 2020
				Hi Star Strider,
What if you had a non symmetric surface i.e. that is several crossections of vectors V1, V2, ... Is there anyway we can interpolate those crossections to come up with a surface?
  Star Strider
      
      
 on 8 Oct 2020
				Taiwo Ajayi —  It might be possible to interpolate them using griddata or griddedinterpolant, or some other appropriate interpolation function.  It would likely be necessary to concatenate them into a matrix first.  I’m speculating here, because I have no idea what the data are.  It will be necessary to experiment to see what works.  
More Answers (0)
See Also
Categories
				Find more on Surface and Mesh Plots in Help Center and File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!


