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How to separate matrix elements based on randomized indices

Asked by Andrew Luce on 14 Jun 2019
Latest activity Answered by Star Strider
on 14 Jun 2019
Hello so I have a matrix like such made up of x's and y'x...say it is a 2x10 array
a=[ 1 2 3 4 5 6 7.... ;
2 3 4 5 6 7 8....]
Say I want to separate the columns in the array this into three arrays with unequal amount of eleements... where the choice of which column goes into what group is random.
lets say the groups contain 5,3 and 2 elements respectfully.
how would one do this in the form of a loop
I wish to be able to plot the three groups as dots of three differnt colors to represent the groups
I was thinking of using randperm(10,10) for the random indeces for picking random columns because there would be no repeats
Thank you

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2 Answers

Answer by KALYAN ACHARJYA on 14 Jun 2019
Edited by KALYAN ACHARJYA on 14 Jun 2019

a=rand(2,10)
[rows colm]=size(a);
rand_colm=randi(colm-3);
mat1=a(:,1:rand_colm)
mat2=a(:,rand_colm+1)
mat3=a(:,rand_colm+2:end)

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Answer by Star Strider
on 14 Jun 2019

If you want, you can do it without an expressed loop (the accumarray function of course loops internally):
a = randi(9,2,10); % Create Matrix
k = randperm(10); % Column Indices
g = [ones(1,5) ones(1,3)*2 ones(1,2)*3]; % Gouping Vector
Out = accumarray(g', k', [], @(x){a(:,x)}); % Assign Outputs
FirstFive = Out{1} % Look At First Group
The grouping vector assigns the random column assignments created by randperm.

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