Why is the maximum length of a datetime array 142?

Hello,

I am trying to initialize a vector of datetime arrays and I can't go beyond a length of 142. Why is that? Is there a workaround?

Here's my code:

datetime_array = NaT(1,length(myTimeStamps));
for i=1:length(datetime_array)
     datetime_array(i,:) = datetime(myTimeStamps(i,:);
end

Error: Index in position 1 exceeds array bounds (must not exceed 142).

Thank you,

Lindsey

[Walter Roberson]

Be careful with length() as it is the maximum dimension, not the number of rows necessarily. Your array might be 142 by something larger than 142.

[Adam Danz]

Datetime array can be much longer than 142. This one below is 10,000 timestamps long.

datetime(1950,1:10000,1)

What is stored in myTimeStamps? Could your provide an example? Perhaps one of them is empty.

[LMA]

Thank you all for your feedback! i see my issue.

Answer 1

[Star Strider]

The ‘142’ value is most likely the row size of the datetime array in your code, and you are apparently addressing it beyond that limit.

[Adam Danz]

Hmmm I was thinking that the 142 might be the number of columns in myTimeStamp. As Walter pointed out, length() seems to have returned a value greater than 142 and since the loop is row-wise and fails, it must have less than 142 rows.

[LMA]

You all above are correct. I have committed a really basic error regarding array dimensions which is causing this problem. Thank you for taking the time nonetheless!

[Guillaume]

The morale of the story is never use length. If you mean the length of a vector, use numel, and if you're operating on a matrix, use size with an explicit dimension.

[LMA]

True that