Looping for storing differet matrix in different rows but in same matrix.

Hello everyone,

I have got a 3x2 cell "alpha_data" in which each cell consists of 1x79 matrixs in them (shown below Fig2). I want to get all these 1x79 matrixes in one matrix "Calculated_Data", so as to have a final matrix of 6x79. i.e. All data into one matrix with all individuals cell matrixs goes into one matrix different rows. I wrote this code but its only giving me one alpha_data{3,2} (Fig 1)data into "Calculated_Data" matrix

for i = 1:size(alpha_data,1) %size(alpha_data,1) = 3
    for j = 1:size(alpha_data,2) %size(alpha_data,1) = 2
        Calculated_Data = vertcat(alpha_data{i,j});
    end
end

The above code that I wrote is only giving one cell's data into final matrix.

Fig1. "Calculated_Data"only giving me one alpha_data{3,2} , but I need 6x79 (all data in the same matrix)

Fig 2. alpha_data: A 3x2 cell, each cell have 1x79 matrix

Any helps would be greately appreacited.

Answer 1

[Vladimir Sovkov]

Before the loop, initiate

Calculated_Data=zeros(numel(alpha_data),numel(alpha_data{1,1}));
k=0;

within the loop, use

k=k+1;
Calculated_Data(k,:) = alpha_data{i,j};

[Darpan Verma]

Works like a cake. Thanks mate.

Answer 2

[Bhaskar R]

In simple way

 Calculated_Data = reshape([alpha_data{:}],6,79);

In for loop

 Calculated_Data = zeros(6, 79);
 k = 1; % counter variable
for i = 1:size(alpha_data,1) %size(alpha_data,1) = 3
    for j = 1:size(alpha_data,2) %size(alpha_data,1) = 2
        Calculated_Data(k,:) = alpha_data{i,j};
        k = k+1;
    end
end

[Vladimir Sovkov]

The "simple" version looks OK.

The "loop" version will not work as both alpha_data{i,j} and alpha_data{j,i} try to occupy the same row of Calculated_Data.

[Bhaskar R]

Yes, my apologies

[Darpan Verma]

Thanks for replying mate