How to integrate a signal sawtooth?
7 views (last 30 days)
Show older comments
moustafa abada
on 6 Mar 2020
Commented: Star Strider
on 6 Mar 2020
I'm integrrating the signal sawtooth using the function "integral" such that "0" min limit and "i" is the max limit to get values of theta to plot it with time but there is an error 'Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.'
Can you help please ?
fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=[];
for i = (0:1/fs:2)
theta=2*pi*kf*integral(signal,0,i);
end
plot(t,theta[i])
0 Comments
Accepted Answer
Star Strider
on 6 Mar 2020
Try this:
fs = 1000;
kf=1000;
t = 0:1/fs:2;
signal = @(tt) sawtooth(pi*2*tt+pi);
theta=zeros(size(t));
for i = 1:numel(t)
theta(i)=integral(signal,0,t(i));
end
figure
plot(t,theta)
It is necessary here to subscript ‘t’ and ‘theta’ in the loop to create the desired vectors.
2 Comments
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!