why the while loop with two conditions don't verify the second condition ?

aff=zeros(6,4);
s1=sum(aff(1:6,1:4),1);
s2=sum(aff(1:6,1:4),2);
sol_aff=[6 2 2 2];
m=zeros(6,1);
for i=1:6
   m(i)=2; 
end
p1=1;
p2=1;
while    (p1 ~= 0   ) && (p2 ~= 0)
    
  aff=randi([0 1],6,4);
  
  s1=sum(aff,1);
  s2=sum(aff,2);
  
    p1=sum(abs(s1-sol_aff)) ;
    p2=sum(abs(m-s2));
end

[madhan ravi]

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Answer 1

[Cris LaPierre]

What is it not doing that it should be doing?

After simplying your code, the first time I ran it, it stopped when p2==0 (the second condition of your while loop).

aff=zeros(6,4);
sol_aff=[6 2 2 2];
m=2*ones(6,1);

p1=1;
p2=1;
while p1 ~= 0 && p2 ~= 0
    aff=randi([0 1],6,4);
    
    s1=sum(aff,1);
    s2=sum(aff,2);
  
    p1=sum(abs(s1-sol_aff))
    p2=sum(abs(m-s2))
end

Since I left the semicolon off for p1 and p2, here is a same of the results of each loop.

p1 = 8
p2 = 4
p1 = 7
p2 = 7
...
p1 = 4
p2 = 4
p1 = 8
p2 = 0

[tlig zied]

I want that while loop stop when p1 and p2 both equal to 0

[Cris LaPierre]

Ah, then change your condition to or (||).

[Torsten]

Then you must use || instead of &&