recursive function to calculate Max number.

function mx=recursive_max(v)
if numel(v)==1
mx=v;
end
if numel(v)>1
mx= recursive_max(1);
end
this much i've got so far.
Please help with this code.

1 Comment

When we use this,it shows error as
incorrectRandom vector Variable mx has an incorrect value. Test failed using v =[ 14 92 89 27 8 ]

Sign in to comment.

 Accepted Answer

Stephen23
Stephen23 on 10 Sep 2020
Edited: Stephen23 on 10 Sep 2020
Urmish Haribhakti's general approach is quite good, with a few small changes it will work correctly:
function x = recmax(v)
if numel(v)<=1
x = v;
else
x = recmax(v(2:end));
if v(1)>x
x = v(1);
end
end
end
And tested:
>> recmax([28,2,6,1,999,8])
ans = 999

More Answers (5)

One more
function mx = recursive_max(v)
if length(v)==1
mx=v
else
if v(1)<=v(2)
v(1)=[]
else
v(2)=[]
end
mx=recursive_max(v)
end

1 Comment

This works for me and is easy to understand! if v(1) < v(2), we remove the first element, and if v(2)<v(1), we remove the v(2), that way we only keep the larger of the 2 elements in the vector. The last remaining element will naturally be the largest one.

Sign in to comment.

Something like this:
function mx = recursive_max(v)
x = zeros(1, 2);
if numel(v) > 2
a = floor(numel(v)/2);
x(1) = recursive_max(v(1:a));
x(2) = recursive_max(v(a+1:end));
elseif numel(v) == 1
x = [v -inf];
else
x = v;
end
if x(1) > x(2)
mx = x(1);
else
mx = x(2);
end
end
I am not sure if this is an optimal algorithm.

2 Comments

can you explain the code....
It divides the input vector into two parts recursively. When the length of the divided vector reaches two during recursion, the recursion stops, and the function returns back the largest of the two elements.

Sign in to comment.

Write a function called recursive_max that finds the maximum element in a vector without using loop or any built in functions.the sole output argument is the maximum value in the input vector.
function output= recursive_max3(v)
if v(1,:)==0
output=v(1);
else
if v(end)>=v
output=v(end);
else
output= recursive_max3(v(1:end-1));
end
end
end
my solution to this assignment is
function mx = my_recursive_max(v)
% base case
if length(v) == 1
mx = v;
else
% recursive case
a = v(end);
b = v(1);
if a <= b
mx = b;
mx = my_recursive_max(v(1:end-1))
else
mx = a;
mx = my_recursive_max(v(2:end))
end
end

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!