Conditional equations with cell arrays.
7 views (last 30 days)
Show older comments
Nickolai Martonick
on 11 Nov 2020
Commented: Star Strider
on 12 Nov 2020
I have two cell arrays as an example. One cell array has positive values, one array has negative values. The cell array with negative values also has zeros.
y = {0 0 0 -179.4 0 -179.3 -178.3 -173.2 -178.9 -179.6}
x = {173.5 169.4 177.5 172.8 169.8 166.6 179.2 178.0 169.7 174.5}
The values represent maximum degrees of movement. The y array is the maximum negative component (if there was one) and the x array is the minimum positive component. 180 (or zero) equals an upright torso and no range of motion. I need to find out the total range of motion. For example the total range of motion between the first values in each array is 6.5 (180 - 173.5). If there is a maximum negative value as with the fourth movement, the range of motion would be 7.8 ((180 - abs(y{4}) + (180 - x{4})). I want to write a statement that performs one equation if there is a zero (180 - 173.5) and another if there is not a zero ((180 - abs(y{4}) + (180 - x{4})) and creates a new cell array of values {1:10}. I have tried the below for loop with if else statement without success. If I put the value of the cell in the place of i, the correct value is displayed. Otherwise for i, I get a single value that is 5.4 and I don't know where it comes from. If I write the loop with ROM{i} then there is an error.
for i = 1:length(y);
if y{i} == 0
ROM = (180 - x{i});
elseif y{i} < 0
ROM = (180 - abs(y{i})) + (180 - x{i});
else
end
end
Help appreciated.
0 Comments
Accepted Answer
Star Strider
on 12 Nov 2020
In one line with ‘logical indexing’:
y = {0 0 0 -179.4 0 -179.3 -178.3 -173.2 -178.9 -179.6};
x = {173.5 169.4 177.5 172.8 169.8 166.6 179.2 178.0 169.7 174.5};
fcn = @(x,y) (180-[x{:}]).*([y{:}]==0) + ((180 - abs([y{:}])) + (180 - [x{:}])).*([y{:}]<0);
ROM = fcn(x,y)
producing:
ROM =
Columns 1 through 7
6.5 10.6 2.5 7.8 10.2 14.1 2.5
Columns 8 through 10
8.8 11.4 5.9
To use the loop, index ‘ROM’. The ‘logical indexing’ approach is faster and more efficient.
2 Comments
Star Strider
on 12 Nov 2020
As always, my pleasure!
The ‘@’ creates a function handle, here specifically denoting an anonymous function.
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!