i wanna to plot the eulars formula on matlab with 3d plot

t = -1:1:1;

eulars formual

x= cos(wt)+jsin(wt);

we shoul have 3d plot like this

sig=2;
x = cos(sig*t) + sin(sig*t)*i;
z= cos(sig*t);
y=sin(sig*t)*i;


plot3(x,y,z)

Answer 1

[Star Strider]

Try this —

t = linspace(0, 3*pi);
sig=2;
x = cos(sig*t) + sin(sig*t)*1i;
z = cos(sig*t);
y = sin(sig*t)*i;

figure
plot3(t,real(x)+0.5,imag(x)+0.5, 'LineWidth',2)
hold on
plot3(t, real(x), zeros(size(x))-1, 'LineWidth',2)
plot3(t, zeros(size(x))+2, imag(x), 'LineWidth',2)
hold off
grid on

I will let you experiment with to understand how it works!

.

Answer 2

[Jan]

t = linspace(-1, 1, 200);
r = cos(2 * pi * t) + 1i * sin(2 * pi * t);

figure;
plot3(t, real(r), imag(r), 'Color', 'k', 'LineWidth', 3);
hold('on');
plot3(t, repmat(-2, size(r)), imag(r), 'Color', 'k', 'LineStyle', '-');
plot3(t, real(r), repmat(-2, size(r)), 'Color', 'k', 'LineStyle', '-.');

axis equal
xlabel('t (sec)');
ylabel('Real Axis');
zlabel('Imag Axis');
xlim([-2, 2])
ylim([-2, 2])
grid('on');
view(-120, 20);

Do you see, that the imaginary axis is mirrored compared to your diagram? Your diagram shows:

r = cos(2 * pi * t) - 1i * sin(2 * pi * t);
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