That's not the correct definition of the concept of "weighted average". Instead, it's rather the average product of two data vectors x and w.
I agree with yurenchu. If you want to choose Problems to translate, then first read all comments made about the original Problem statement to see if there are any important critiques to heed. If so, then either address the critiques and create an improved version of the Problem, or else choose a different original Problem.
Changed the translation
Very good :-)
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office