Problem 1103. Right Triangle Side Lengths (Inspired by Project Euler Problem 39)

Created by @bmtran (Bryant Tran)

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Solve

Solution Stats

2040 Solutions
513 Solvers

Last Solution submitted on Jan 20, 2021

Last 200 Solutions

Problem Comments

3 Comments

3 Comments

Vishal on 13 Oct 2020

Hi Team,

I am getting error after submitting as,

"We're sorry, but something went wrong. We've been notified about this issue and we'll take a look at it shortly"

But completion bar has been incremented.
Thanks and Have a Good DaY

肇优孙 on 27 Dec 2020 at 8:42

function A = right_triangle_sides(p)
k=1;
for i=1:round(p/2)
for j=1:p-i
if sqrt(i^2+j^2)==p-i-j
c(k,:)=[i,j,p-i-j];
k=k+1;
end
end
end
c(size(c,1)/2+1:size(c,1),:)=[];
for i = 1:size(c,1)
A{1,i}=c(i,:);
end
end

学凯刘 on 10 Jan 2021 at 7:47

Well I don't know why I can't pass the test
could anyone help

function c = right_triangle_sides(p)
c = {};
k=1;
for i=1:ceil(p/3)
for j=i:ceil((p-i)/2)
if i^2+j^2==(p-i-j)^2
c(k)=mat2cell([i j p-i-i],1);
k=k+1;
end
end
end
end

Solution Comments

Solution 4368870

1 Comment

1 Comment

WK C on 20 Dec 2020

function c = right_triangle_sides(p)
i=0;
for a1 = 1:p-2
for a2 = a1:(p-a1-1)
for a3 = a2:(p-a2-1)
if((a1^2+a2^2==a3^2)&&(a1<=a2)&&(a2<=a3)&&(a1+a2+a3==p))
i=i+1;
b(i,:) = [a1,a2,a3];
end
end
end
end
for i = 1:size(b,1)
c{1,i}=b(i,:);
end
end

Solution 3935418

1 Comment

1 Comment

Hee Jason on 1 Dec 2020

function c = right_triangle_sides(p)
N = round(p/2);
A = 1:N;
A = A.^2;
B = sqrt(A + A');
C = arrayfun(@(t) t/floor(t) == 1,B);
[i j] = find(triu(C));
k = p - i - j;
x = (i.^2 + j.^2 - k.^2 == 0);
R = [i(x) j(x) k(x)];
R = sortrows(R);
R = R';
[~,col] = size(R);
c = mat2cell(R(:)',1,3*ones(1,col));
end

Solution 3597510

Solution 2813128

2 Comments

2 Comments

Sergio Enrique Pinto Castillo on 9 Aug 2020

I think, the statement of the problem is not complete. The reference problem is not available. I know very well about right angle triangles but I do not have the idea on how to find the solutions. Please help me out.

Vishal on 13 Oct 2020

Hi Castillo,
it is just iteration of 3 sides using perimeter and summing up the three iteration variable for perimeter check then for right angle triangle check (Pythagoras)...
Hope this helped you...(:

Solution 2593735

2 Comments

2 Comments

Piero Cimule on 22 Jun 2020

c=[];
for A=1:p
B=0;
while B < 1000
B = B+1;
C = sqrt((A^2) + (B^2));
perimeter = A+B+C;
if perimeter==p
c(end+1,:) = [A,B,C];
end
end
end
c=unique(sort(c,2),'rows');
x=cell(1,size(c,1));
for i=1:size(c,1)
[x{1,i}]= deal(c(i,:))
end
c=x

Marek Macák on 25 Nov 2020

Thank you :)

Solution 2055983

1 Comment

1 Comment

Miles Walker on 12 Dec 2019

Works, but is horribly inefficient especially for higher p...

Solution 174395

1 Comment

1 Comment

Aurelien Queffurust on 18 Dec 2012

solution using a Neural Network Toolbox function ;)

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Problem 1103. Right Triangle Side Lengths (Inspired by Project Euler Problem 39)

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Problem 1103. Right Triangle Side Lengths (Inspired by Project Euler Problem 39)

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Last 200 Solutions

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Solution Comments

Problem Recent Solvers513

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More from this Author56

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