Does r=uint64(308436464205151562) make sense? It seems like the argument to uint64 is a double precision number, so you have already lost the precision you are trying to gain by using uint64.
r=uint64(308436464205151562) outputs for uint64(r) 308436464205151562. However, r=308436464205151562 outputs for uint64(r) 308436464205151552. A very small loss in precision, but still a loss. The Challenge set has some numbers that use all the paint if full precision math was used. If residual paint was required as an output then full precision is needed. For solutions using p=p-2*r-1 the errors in r and p may cause issues.
Very novel input parameter adjustment to allow direct solution.
Nice bisecting search method and anonymous function for clean appearance.
Reverse Run-Length Encoder
Factorize THIS, buddy
Energy of a photon
Rotate and display numbered tile
GJam: 2013 China Event: Name Sorting
GJam 2014 China Rd A: Rational Number Tree (Large Values)
Kaggle: Reverse Game of Life - Periods of Oscillators
Angle between Two Vectors
Geometry: Find Circle given 3 Non-Colinear Points
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