given the 1x5 vector x, y must be the square of the horizontal concatenation of the third and fifth elements. So, if x = [1 1 1 1 1], y must be [1 1].
The example you give in the problem statement is not very demonstrative.
HAHAHAHA Matt: this was great!!!
Distance walked 1D
07 - Common functions and indexing 5
07 - Common functions and indexing 6
Hard limit function
Matlab Basics II - Minimum
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