Consider the integer triangle below:
It follows the same rule as Pascal's Triangle, except that instead of affixing 1's at the sides of each row, the row number minus 1, is affixed (on first row 0 is affixed; at row 2, 1 is affixed on each side, etc.). Any inner number, as in Pascal's Triangle, is the sum of the left and right numbers on its previous row.
Given a number n find , which is the sum of the n-th row. Hence, and .
We could be getting large numbers here, therefore please concatenate the total number of digits with the last 3 digits of and output a single concatenated integer. For example the , hence the output should be .
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Last Solution submitted on May 24, 2026

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Chris Cleveland George Berken Augusto Mazzei Mehdi Dehghan

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