Problem 672. Longest run of consecutive numbers

Created by James

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Given a vector a, find the number(s) that is/are repeated consecutively most often. For example, if you have

a = [1 2 2 2 1 3 2 1 4 5 1]

The answer would be 2, because it shows up three consecutive times.

If your vector is a row vector, your output should be a row vector. If your input is a column vector, your output should be a column vector. You can assume there are no Inf or NaN in the input. Super (albeit non-scored) bonus points if you get a solution that works with these, though.

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Last Solution submitted on Apr 04, 2020

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Aurelien Queffurust on 21 Jun 2012

I don't understand why for test suite 4 :
a=[0 1 1 1 0 2 2 0 1 1 1 0];
y_correct = [1 1];
I expect y_correct = [1 1 1]

Tim on 21 Jun 2012

The idea seems to be to return the element that occurs in the longest run, or all such elements in case of a tie. In case 4 there are two longest runs, both with element 1.

Aurelien Queffurust on 22 Jun 2012

Thanks Tim for the explanation . So as the vector [1 1 1] appears twice in test 4 with the unique value 1 , the result must be twice the unqiue value -> [ 1 1]. ok ok thanks again

Azmi Yagli on 25 Mar 2020 at 15:28

Nice

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Solution 2043151

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Jack Shadow on 3 Dec 2019

It was not so easy...

Solution 1619892

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David Motson on 19 Nov 2019

What kind of solution is that?

Gustavo Morales on 22 Nov 2019

that's a bug of Matlab Cody, the use of ! and regexp.
I don't know why Mathworks has it not corrected.

BoredBean on 10 Feb 2020

Can't understand a bit of this code.

Matteo Baldan on 14 Mar 2020 at 19:54

i'd really like to see a better solution that mine, one that uses difference equations..mine is size 129 and is just a control loop. Guess i've got to search in solution map.

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consecutive repeating vectors

Problem 672. Longest run of consecutive numbers

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Problem 672. Longest run of consecutive numbers

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