Problem 796. Removing rows from a matrix is easy  but what about inserting rows?
Assume A is a 5by5 matrix. A([2,4],:) = [] is a quick way to remove rows 2 and 4. Can you find a quick way to insert rows into A?
You are given a nbym matrix A, a 1byp vector of indices IND, and either a scalar value (1by1) or a pbym matrix b to be inserted AFTER rows IND of A. In case of a scalar value it should fill the whole row. Note that IND may contain duplicate indices, which means that more than one row should be inserted after that specific row index.
For example:
A = [1 1; 3 3; 4 4]; IND = [1 3]; b = [2 2; 5 5];
should become
y = [1 1; 2 2; 3 3; 4 4; 5 5];
And
A = [0 0; 1 1]; IND = [1 1 2]; b = NaN;
should become
y = [0 0; NaN NaN; NaN NaN; 1 1; NaN NaN];
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Problem Comments

4 Comments
Many of the test cases are wrong.
For example:
A = (1:2:10)';
IND = 1:5;
b = (2:2:10)';
y_correct = (1:10)';
y_correct should be [2:2:10,1:2:10]'
The zeros one has zeros that are the wrong size etc.
I corrected one error regarding isequal with NaNs, but all the other test cases are correct.
A = [1 3 5 7 9]; IND = [1 2 3 4 5]; b = [2 4 6 8 10]; definitely should result in [1 2 3 4 5 6 7 8 9 10]! You have to insert b(1) after A(1), b(2) after A(2) and so on.
Nice problem, but the specification could be improved: from the description, you'd think the entire matrix b is supposed to be inserted after each row in IND; it's only the first example that makes it clear that this is not the case.
A good problem. My first attempts at solutions used for loops and if statements, but as some of the correct submissions demonstrated, you don't need either of these to solve this problem. Vectorization is your friend.
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