Why is the Nyquist frequncy on the bode diagrams the same as the sampling frequency?
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Nathan Sisson
on 13 Nov 2024 at 22:23
Commented: Voss
on 13 Nov 2024 at 23:07
I notice that when I create a discrete dynamical system with a given sampling frequency, and I plot the bode diagrams, the phase and amplitude responses are plotted up to the samping frequency. On the documentation page for the bode command, it calls this upper limit on the frequency the Nyquist frequency. Even in their example, this Nyquist frequency is exactly the same as the sampling frequency. They create a system with a sampling time of 0.5 seconds (2 Hz, or 6.28 rad/s) and the resulting bode diagrams go up to 6.28 rad/s. So why is this the case, when I know that the Nyquist frequency is defined as half of the sampling frequency?
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Voss
on 13 Nov 2024 at 22:42
"sampling time of 0.5 seconds (2 Hz, or 6.28 rad/s)"
There's the problem. 2 Hz is 2*2*pi rad/s = 4*pi rad/s, which is approx 12.56 rad/s (not 6.28 rad/s).
Thus the corresponding Nyquist frequency is half of that or approx 6.28 rad/s.
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